Chapter 4 Study Questions
1. Classify each of the following substances as: 1) acid, base, or neutral, and 2) strong or weak. Then 3) write a balanced equation for the ionization of the substance in water:
a) HNO3 b) HClO c) NH3 d) NaNO3 e) Ba(OH)2
2. A common method of preparing solutions is to make up a concentrated solution and then dilute it to the desired concentration.
a) What is the molarity of a solution prepared by dissolving 29.2 g NaCl in enough water to make 0.250 liters of solution?
b) What volume of the above solution is needed to make 125 ml of a 0.350 M NaCl solution?
3. What mass of glucose (C6H12O6) is needed to prepare 200.0 ml of a 2.50 M glucose solution?
4. Solid magnesium is added to 125 ml of 2.00 M hydrochloric acid to produce dissolved magnesium chloride and hydrogen gas.
a) Write a balanced equation for this reaction.
b) If excess magnesium is added, how many moles of hydrogen gas are produced?
5. Indicate whether a precipitate will form when the following solutions are mixed. If a precipitate forms, write a net ionic equation for the reaction.
a) iron(III) nitrate and potassium hydroxide
b) ammonium chloride and lithium carbonate
c) sodium sulfide and nickel(II) sulfate
6. Name two solutions which could be mixed to form strontium sulfate.
7. Write a balanced net ionic equation for the acid-base reaction between HNO3 with KOH.
8. How many ml of 2.00 M NaOH would be required to neutralize 12.5 ml of 0.0800 M HBr?
9. When solutions of lead(II) nitrate and aluminum chloride are mixed, a precipitate forms.
a) Write a balanced formula equation for the reaction.
b) What volume of a 0.200 M lead(II) nitrate solution is needed to completely form a precipitate when added to 2.48 mL of 0.300 M aluminum chloride?
c) What is the mass of precipitate formed in (b)?
10. What mass of precipitate is formed when 71.3 mL of 0.500 M iron(III) nitrate are mixed with 112 mL of 0.800 M sodium carbonate?
11. How many ml of 2.50 M HNO3 contain enough nitric acid to dissolve an old copper penny with a mass of 3.94 grams?
3 Cu(s) + 8 HNO3(aq) à 3 Cu(NO3)2(aq) + 2 NO(g) + 4 H2O
Summary of Chapter 4: Chemical Reactions in Water Solutions
solute, solvent, solubility
electrolytes & nonelectrolytes
strong vs. weak electrolytes
calculations involving molarity
finding the molarity of a solution
using molarity as a conversion factor
dilution: V1 x M1 = V2 x M2
reading a solubility table
complete ionic equations
net ionic equations
stoichiometry of precipitation reactions